Find the distance d( $$\mathrm { d } \left( \mathrm { P } _ { 1 } , \mathrm { P } _ { 2 } \right) \text { between the points } \mathrm { P } _ { 1 } \text { and } \mathrm { P } _ { 2 }$$ .
-$$\mathrm { P } _ { 1 } = ( 4,3 ) ; \mathrm { P } _ { 2 } = ( - 2,11 )$$
A) 100
B) 20
C) 11
D) 10

Question

Quizplus · Accepted Answer

The distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ in a plane is given by the formula $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$. Applying this formula to the given points $P_1 = (4,3)$ and $P_2 = (-2,11)$, we get $\sqrt{(-2 - 4)^2 + (11 - 3)^2} = \sqrt{(-6)^2 + (8)^2} = \sqrt{36 + 64} = \sqrt{100} = 10$.

Find the Distance D - P1=(4,3);P2=(−2,11)\mathrm { P } _ { 1 } = ( 4,3 ) ; \mathrm { P } _ { 2 } = ( - 2,11 )P1​=(4,3);P2​=(−2,11)

Find the Distance D
- $\mathrm { P } _ { 1 } = ( 4,3 ) ; \mathrm { P } _ { 2 } = ( - 2,11 )$