Solve the problem.
-Let $P = ( x , y )$ be a point on the graph of $y = \sqrt { x }$. Express the distance $d$ from $P$ to the point $( 1,0 )$ as a function of $x$
A) $d ( x ) = x ^ { 2 } - x + 1$
B) $d ( x ) = x ^ { 2 } + 2 x + 2$
C) $\mathrm { d } ( \mathrm { x } ) = \sqrt { \mathrm { x } ^ { 2 } + 2 \mathrm { x } + 2 }$
D) $d ( x ) = \sqrt { x ^ { 2 } - x + 1 }$

Question

Quizplus · Accepted Answer

The distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$. Here, $P = (x, \sqrt{x})$ and the point is $(1, 0)$, so $d(x) = \sqrt{(x - 1)^2 + (\sqrt{x} - 0)^2} = \sqrt{x^2 - 2x + 1 + x} = \sqrt{x^2 - x + 1}$.

Solve the Problem P=(x,y)P = ( x , y )P=(x,y) Be a Point on the Graph Of

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