Solve the problem.
-If an object is thrown straight upward from the ground with an initial speed of 112 feet per second, then its height, h, in feet after t seconds is given by the equation $$h ( t ) = - 16 t ^ { 2 } + 112 t$$ Find the instantaneous speed of the
Object at t = 6.
A) 112 ft/sec
B) -464 ft/sec
C) -80 ft/sec
D) 16 ft/sec

Question

Quizplus · Accepted Answer

The instantaneous speed is the derivative of the height function with respect to time. The derivative of $h(t) = -16t^2 + 112t$ is $h'(t) = -32t + 112$. Evaluating this at $t = 6$ gives $h'(6) = -32(6) + 112 = -192 + 112 = -80$ ft/sec.

Solve the Problem h(t)=−16t2+112th ( t ) = - 16 t ^ { 2 } + 112 th(t)=−16t2+112t

Solve the Problem $h ( t ) = - 16 t ^ { 2 } + 112 t$