Find the complex zeros of the quadratic function.
-$$h ( x ) = x ^ { 2 } - 12 x + 61$$
A) $x = 1 , x = 11$
B) $x = 6 - 5 i , x = 6 + 5 i$
C) $x = 6 + 5 i$
D) $x = 6 - 25 i , x = 6 + 25 i$

Question

Quizplus · Accepted Answer

The quadratic formula, $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, applied to $h(x) = x^2 - 12x + 61$ gives $x = \frac{12 \pm \sqrt{(-12)^2 - 4(1)(61)}}{2(1)} = \frac{12 \pm \sqrt{144 - 244}}{2} = \frac{12 \pm \sqrt{-100}}{2} = 6 \pm 5i$, indicating complex roots $6 - 5i$ and $6 + 5i$.

Find the Complex Zeros of the Quadratic Function h(x)=x2−12x+61h ( x ) = x ^ { 2 } - 12 x + 61h(x)=x2−12x+61

Find the Complex Zeros of the Quadratic Function $h ( x ) = x ^ { 2 } - 12 x + 61$