Use factoring to find the zeros of the quadratic function. List the x-intercepts of the graph of the function.
-$$f ( x ) = x ^ { 2 } + 6 x - 40$$
A) $x = - 10 , x = 1$
B) $x = 10 , x = - 4$
C) $x = 10 , x = 4$
D) $x = - 10 , x = 4$

Question

Quizplus · Accepted Answer

To find the zeros of the quadratic function $f(x) = x^2 + 6x - 40$, we factor it. The factors of -40 that add up to 6 are 10 and -4. Therefore, the factored form is $f(x) = (x + 10)(x - 4)$. Setting each factor equal to zero gives the solutions $x = -10$ and $x = 4$, which are the x-intercepts of the graph.

Use Factoring to Find the Zeros of the Quadratic Function f(x)=x2+6x−40f ( x ) = x ^ { 2 } + 6 x - 40f(x)=x2+6x−40

Use Factoring to Find the Zeros of the Quadratic Function $f ( x ) = x ^ { 2 } + 6 x - 40$