Determine I) the Domain of the Function, Ii) the Range $$f ( x ) = \sqrt { 5 x + 4 }$$

Determine i) the domain of the function, ii) the range of the function, iii) the domain of the inverse, and iv) the range of
the inverse.
- $$f ( x ) = \sqrt { 5 x + 4 }$$

A) $f ( x ) : D = \left\{ x \mid x \geq - \frac { 4 } { 5 } \right\} , R = \{ y \mid y \geq 0 \}$ ;
$\mathrm{f}^{-1}(\mathrm{x}) \text { : } \mathrm{D} \text { is all real numbers, } \mathrm{R}=\left\{\mathrm{y} \mid \mathrm{y} \geq-\frac{4}{5}\right\}$

B) $\begin{array}{l}f(x) : D=\left\{x \mid x \geq-\frac{4}{5}\right\}, R=\{y \mid y \geq 0\} \\f^{-1}(x) : D=\{x \mid x \geq 0\}, R=\left\{y \mid y \geq-\frac{4}{5}\right\}\end{array}$


C) $\mathrm{f}(\mathrm{x}) : \mathrm{D}=\left\{\mathrm{x} \mid \mathrm{x} \geq-\frac{4}{5}\right\}, \mathrm{R}$ is all real numbers; $\mathrm{f}^{-1}(\mathrm{x})$ : D is all real numbers, $\mathrm{R}=\left\{\mathrm{y} \mid \mathrm{y} \geq-\frac{4}{5}\right\}$

D) $\begin{array}{l}f(x) : D=\{x \mid x \geq 0\}, R=\{y \mid y \geq 0\} \\f^{-1}(x) : D=\{x \mid x \geq 0\}, R=\left\{y \mid y \geq-\frac{4}{5}\right\}\end{array}$