Solve the problem.
-For what numbers $x , - 2 \pi \leq x \leq 2 \pi$, does the graph of $y = \tan x$ have vertical asymptotes.?
A) $- 2 \pi , - \pi , 0 , \pi , 2 \pi$
B) $- \frac { 3 \pi } { 2 } , - \frac { \pi } { 2 } , \frac { \pi } { 2 } , \frac { 3 \pi } { 2 }$
C) $- 2 , - 1,0,1,2$
D) none

Question

Quizplus · Accepted Answer

The graph of $y = \tan x$ has vertical asymptotes where the cosine function, which is the denominator in the tangent function, equals zero. This occurs at $x = \pm \frac{\pi}{2}, \pm \frac{3\pi}{2}$ within the given interval $-2\pi \leq x \leq 2\pi$.

Solve the Problem x,−2π≤x≤2πx , - 2 \pi \leq x \leq 2 \pix,−2π≤x≤2π

Solve the Problem $x , - 2 \pi \leq x \leq 2 \pi$