Solve the problem. -Before exercising, an athlete measures her air flow and obtains $a = 0.65 \sin \left( \frac { 2 \pi } { 5 } t \right)$ where a is measured in liters per second and t is the time in seconds. If a 0, the athlete is inhaling; if a

Question

Solve the problem.
-Before exercising, an athlete measures her air flow and obtains $a = 0.65 \sin \left( \frac { 2 \pi } { 5 } t \right)$ where a is measured in liters per second and t is the time in seconds. If a > 0, the athlete is inhaling; if a < 0, the athlete
is exhaling. The time to complete one complete inhalation/exhalation sequence is a respiratory cycle.
What is the amplitude? What is the period? What is the respiratory cycle?
Graph a over two periods beginning at t = 0.

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The Answer of Solve the problem.
-Before exercising, an athlete measures her air flow and obtains $a = 0.65 \sin \left( \frac { 2 \pi } { 5 } t \right)$ where a is measured in liters per second and t is the time in seconds. If a > 0, the athlete is inhaling; if a < 0, the athlete
is exhaling. The time to complete one complete inhalation/exhalation sequence is a respiratory cycle.
What is the amplitude? What is the period? What is the respiratory cycle?
Graph a over two periods beginning at t = 0.

Solve the Problem a=0.65sin⁡(2π5t)a = 0.65 \sin \left( \frac { 2 \pi } { 5 } t \right)a=0.65sin(52π​t)

Solve the Problem $a = 0.65 \sin \left( \frac { 2 \pi } { 5 } t \right)$