Solve the problem.
-$\sin \theta = \frac { 2 \sqrt { 2 } } { 3 } , \cos \theta = \frac { 1 } { 3 } \quad$ Find $\csc \theta .$
A) $\frac { \sqrt { 15 } } { 15 }$
B) $\frac { 3 \sqrt { 2 } } { 4 }$
C) $\sqrt { 15 }$
D) $\frac { 4 \sqrt { 15 } } { 15 }$

Question

Quizplus · Accepted Answer

The cosecant function is the reciprocal of the sine function. Therefore, $\csc \theta = \frac{1}{\sin \theta} = \frac{1}{\frac{2\sqrt{2}}{3}} = \frac{3}{2\sqrt{2}} = \frac{3\sqrt{2}}{4}$.

Solve the Problem sin⁡θ=223,cos⁡θ=13\sin \theta = \frac { 2 \sqrt { 2 } } { 3 } , \cos \theta = \frac { 1 } { 3 } \quadsinθ=322​​,cosθ=31​

Solve the Problem $\sin \theta = \frac { 2 \sqrt { 2 } } { 3 } , \cos \theta = \frac { 1 } { 3 } \quad$