Solve the problem.
-The path of a projectile fired at an inclination $\theta$ to the horizontal with an initial speed vo is a parabola. The range R of the projectile, the horizontal distance that the projectile travels, is found by the formula $\mathrm { R } = \frac { \mathrm { v } _ { \mathrm { O } } ^ { 2 } \sin 2 \theta } { \mathrm { g } }$ where g = 32.2 feet per second per second or g = 9.8 meters per second per second. Find the
Range of a projectile fired with an initial velocity of 174 feet per second at an angle of 35° to the horizontal.
Round your answer to two decimal places.
A) 883.54 ft
B) 883.44 ft
C) 1,078.61 ft
D) 539.30 ft

Question

Quizplus · Accepted Answer

The range R can be calculated using the formula $R = \frac{v_0^2 \sin 2\theta}{g}$. Substituting $v_0 = 174$ feet per second, $\theta = 35^\circ$, and $g = 32.2$ feet per second squared, we get $R = \frac{174^2 \sin(2 \times 35)}{32.2}$, which rounds to 883.54 feet.

Solve the Problem θ\thetaθ To the Horizontal with an Initial Speed Vo Is a an Inclination

Solve the Problem $\theta$ To the Horizontal with an Initial Speed Vo Is a an Inclination