Solve the Problem $F$ , in Newtons, Acting on a String Pendulum Is Given

Solve the problem.
-The force acting on a pendulum to bring it to its perpendicular resting point is called the restoring force. The rest force $F$ , in Newtons, acting on a string pendulum is given by the formula
$$\mathrm { F } = \mathrm { mg } \sin \theta$$
where $\mathrm { m }$ is the mass in kilograms of the pendulum's bob, $g \approx 9.8$ meters per second per second is the acceleration due to gravity, and $\theta$ is angle at which the pendulum is displaced from the perpendicular. What is the value of the restoring force when $\mathrm { m } = 0.7$ kilogram and $\theta = 45 ^ { \circ }$ ? If necessary, round the answer to the nearest tenth of a Newton.

A) $4.7 \mathrm {~N}$
B) $4.6 \mathrm {~N}$
C) $5.8 \mathrm {~N}$
D) $4.9 \mathrm {~N}$