For the Linear Equation $y = 6 + 4 x$ , Explain What The

For the linear equation $y = 6 + 4 x$ , explain what the $y$ -intercept and slope represent in terms of the graph of the equation.

A) The $\mathrm { y }$ -intercept, $\mathrm { b } _ { 0 } = 6$ , gives the $\mathrm { y }$ -value at which the straight line $\mathrm { y } = 6 + 4 \mathrm { x }$ intersects the $x$ -axis. The slope, $b _ { 1 } = 4$ , indicates that the $x$ -value increases by 4 units for every increase in $y$ of 1 unit.
B) The $y$ -intercept, $b _ { 0 } = 4$ , gives the $y$ -value at which the straight line $y = 6 + 4 x$ intersects the $y$ -axis. The slope, $b _ { 1 } = 6$ , indicates that the $y$ -value increases by 6 units for every increase in $x$ of 1 unit.
C) The $y$ -intercept, $b _ { 0 } = 6$ , gives the $y$ -value at which the straight line $y = 6 + 4 x$ intersects the $y$ -axis. The slope, $b _ { 1 } = 4$ , indicates that the $x$ -value increases by 4 units for every increase in $y$ of 1 unit.
D) The $y$ -intercept, $\mathrm { b } _ { 0 } = 6$ , gives the $\mathrm { y }$ -value at which the straight line $\mathrm { y } = 6 + 4 \mathrm { x }$ intersects the $y$ -axis. The slope, $b _ { 1 } = 4$ , indicates that the $y$ -value increases by 4 units for every increase in $x$ of 1 unit.