Find the sample standard deviation for the given data. Round your final answer to one more decimal place than that usedfor the observations.
-The manager of an electrical supply store measured the diameters of the rolls of wire in the inventory. The diameters of the rolls (in m)are listed below. $\begin{array} { l l l l l l l } 0.559 & 0.189 & 0.527 & 0.183 & 0.3 & 0.316 & 0.657 \end{array}$
A)$1.2809 \mathrm {~m}$
B) $1.0655 \mathrm {~m}$
C) $0.1895 \mathrm {~m}$
D) $0.1830 \mathrm {~m}$

Question

Find the sample standard deviation for the given data. Round your final answer to one more decimal place than that usedfor the observations.
-The manager of an electrical supply store measured the diameters of the rolls of wire in the inventory. The diameters of the rolls (in m)are listed below. $\begin{array} { l l l l l l l } 0.559 & 0.189 & 0.527 & 0.183 & 0.3 & 0.316 & 0.657 \end{array}$  
A)$1.2809 \mathrm {~m}$
B) $1.0655 \mathrm {~m}$
C) $0.1895 \mathrm {~m}$
D) $0.1830 \mathrm {~m}$

Quizplus · Accepted Answer

To find the sample standard deviation, first calculate the mean of the data, then use the formula for sample standard deviation. The mean of the data is $\frac{0.559 + 0.189 + 0.527 + 0.183 + 0.3 + 0.316 + 0.657}{7} = 0.3901 \, \text{m}$. Then, for each data point, subtract the mean and square the result, sum these squared differences, divide by $n-1$ (where $n$ is the number of data points, which is 7 in this case), and finally take the square root of that quotient. The correct calculation leads to a sample standard deviation of approximately $0.1895 \, \text{m}$, rounded to one more decimal place than the observations.

Find the Sample Standard Deviation for the Given Data 0.5590.1890.5270.1830.30.3160.657\begin{array} { l l l l l l l } 0.559 & 0.189 & 0.527 & 0.183 & 0.3 & 0.316 & 0.657 \end{array}0.559​0.189​0.527​0.183​0.3​0.316​0.657​

Find the Sample Standard Deviation for the Given Data $\begin{array} { l l l l l l l } 0.559 & 0.189 & 0.527 & 0.183 & 0.3 & 0.316 & 0.657 \end{array}$