Find the mean of the random variable.
-The random variable X is the number of golf balls ordered by customers at a pro shop. Its probability distribution is given in the table. Round the answer to two decimal places when
Necessary. $\begin{array}{c|ccccc}
\mathrm{X} & 3 & 6 & 9 & 12 & 15 \
\hline \mathrm{P}(\mathrm{X}=\mathrm{x}) & 0.14 & 0.29 & 0.36 & 0.11 & 0.10
\end{array}$
A)$9.3$
B) $8.22$
C) $5.55$
D) 9

Question

Quizplus · Accepted Answer

The mean of a random variable is given by the expected value, which is calculated as the sum of the products of each possible value of the random variable and its corresponding probability. In this case, the expected value is:E(X) = 3(0.14) + 6(0.29) + 9(0.36) + 12(0.11) + 15(0.10) = 8.22Therefore, the mean of the random variable is 8.22, which is rounded to 8.22 when necessary.

Find the Mean of the Random Variable X3691215P(X=x)0.140.290.360.110.10\begin{array}{c|ccccc}\mathrm{X} & 3 & 6 & 9 & 12 & 15 \\\hline \mathrm{P}(\mathrm{X}=\mathrm{x}) & 0.14 & 0.29 & 0.36 & 0.11 & 0.10\end{array}XP(X=x)​30.14​60.29​90.36​120.11​150.10​​

Find the Mean of the Random Variable $\begin{array}{c|ccccc}\mathrm{X} & 3 & 6 & 9 & 12 & 15 \\\hline \mathrm{P}(\mathrm{X}=\mathrm{x}) & 0.14 & 0.29 & 0.36 & 0.11 & 0.10\end{array}$