$$\text { When using a truth table, the statement } \sim q \wedge p \text { is equivalent to } \sim q \rightarrow p \text {. }$$

Question

Quizplus · Accepted Answer

The statement $\sim q \wedge p$ means "not q AND p," which is true only when both $p$ is true and $q$ is false. However, the statement $\sim q \rightarrow p$ means "if not q then p," which is true when either $p$ is true or $q$ is true (or both), except for the case when $q$ is false and $p$ is also false. These two statements are not equivalent because they have different truth conditions.

When using a truth table, the statement ∼q∧p is equivalent to ∼q→p. \text { When using a truth table, the statement } \sim q \wedge p \text { is equivalent to } \sim q \rightarrow p \text {. } When using a truth table, the statement ∼q∧p is equivalent to ∼q→p.

$\text { When using a truth table, the statement } \sim q \wedge p \text { is equivalent to } \sim q \rightarrow p \text {. }$