Solve the problem.
-The time, $T$, in seconds required for a pendulum of length $\mathrm { L }$ feet to make one swing is given by $\mathrm { T } = 2 \pi \sqrt { \frac { \mathrm { L } } { 32 } }$. How long is a pendulum (to the nearest hundredth of a foot) if it makes one swing in 2 seconds?
A) $10.19 \mathrm { ft }$
B) $6.48 \mathrm { ft }$
C) $3.56 \mathrm { ft }$
D) $3.24 \mathrm { ft }$

Question

Quizplus · Accepted Answer

To find the length $L$, rearrange the formula: $L = \left(\frac{T}{2\pi}\right)^2 \times 32$. Substituting $T = 2$ gives $L = \left(\frac{2}{2\pi}\right)^2 \times 32 \approx 3.24$ feet.

Solve the Problem TTT , in Seconds Required for a Pendulum of Length

Solve the Problem $T$ , in Seconds Required for a Pendulum of Length