Find the requested probability.
-A box contains the following mixture of colored marbles: 2 black, 1 red, 2 yellow, and 3 green. What is the probability of drawing, in order, a yellow marble, a red marble, and a black marble if The three marbles are drawn without replacement?
A) $\frac { 1 } { 336 }$
B) $\frac { 1 } { 168 }$
C) $\frac { 1 } { 16 }$
D) $\frac { 1 } { 84 }$

Question

Find the requested probability.
-A box contains the following mixture of colored marbles: 2 black, 1 red, 2 yellow, and 3 green. What is the probability of drawing, in order, a yellow marble, a red marble, and a black marble if The three marbles are drawn without replacement? 
A) $\frac { 1 } { 336 }$
B) $\frac { 1 } { 168 }$
C) $\frac { 1 } { 16 }$
D) $\frac { 1 } { 84 }$

Quizplus · Accepted Answer

The probability of drawing a yellow, then a red, then a black marble without replacement is calculated by multiplying the probabilities of each event happening in sequence. The total number of marbles is 8 (2 black, 1 red, 2 yellow, 3 green). The probability of drawing a yellow marble first is 2/8, then the probability of drawing a red marble from the remaining 7 marbles is 1/7, and finally, the probability of drawing a black marble from the remaining 6 marbles is 2/6. Multiplying these probabilities gives (2/8) * (1/7) * (2/6) = 1/84.

Find the Requested Probability 1336\frac { 1 } { 336 }3361​

Find the Requested Probability $\frac { 1 } { 336 }$