Consider the function h as defined. Find functions f and g so tha $( f \circ g ) ( x ) = h ( x )$
-$$h ( x ) = \frac { 1 } { \sqrt { 2 x + 4 } }$$
A) $f ( x ) = \frac { 1 } { \sqrt { x } } , g ( x ) = 2 x + 4$
B) $f ( x ) = \sqrt { 2 x + 4 } , g ( x ) = 1$
C) $f ( x ) = \frac { 1 } { x } , g ( x ) = 2 x + 4$
D) $f ( x ) = 1 , g ( x ) = \sqrt { 2 + 4 }$

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The Answer of Consider the function h as defined. Find functions f and g so tha $( f \circ g ) ( x ) = h ( x )$
-$$h ( x ) = \frac { 1 } { \sqrt { 2 x + 4 } }$$
A) $f ( x ) = \frac { 1 } { \sqrt { x } } , g ( x ) = 2 x + 4$
B) $f ( x ) = \sqrt { 2 x + 4 } , g ( x ) = 1$
C) $f ( x ) = \frac { 1 } { x } , g ( x ) = 2 x + 4$
D) $f ( x ) = 1 , g ( x ) = \sqrt { 2 + 4 }$

Consider the Function H as Defined (f∘g)(x)=h(x)( f \circ g ) ( x ) = h ( x )(f∘g)(x)=h(x)

Consider the Function H as Defined $( f \circ g ) ( x ) = h ( x )$