Consider the function h as defined. Find functions f and g so tha $( f \circ g ) ( x ) = h ( x )$
-$$h ( x ) = \frac { 1 } { x ^ { 2 } - 6 }$$
A) $f ( x ) = \frac { 1 } { x ^ { 2 } } , g ( x ) = x - 6$
B) $f ( x ) = \frac { 1 } { x ^ { 2 } } , g ( x ) = - \frac { 1 } { 6 }$
C) $f ( x ) = \frac { 1 } { x } , g ( x ) = x ^ { 2 } - 6$
D) $f ( x ) = \frac { 1 } { 6 } , g ( x ) = x ^ { 2 } - 6$

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The Answer of Consider the function h as defined. Find functions f and g so tha $( f \circ g ) ( x ) = h ( x )$
-$$h ( x ) = \frac { 1 } { x ^ { 2 } - 6 }$$
A) $f ( x ) = \frac { 1 } { x ^ { 2 } } , g ( x ) = x - 6$
B) $f ( x ) = \frac { 1 } { x ^ { 2 } } , g ( x ) = - \frac { 1 } { 6 }$
C) $f ( x ) = \frac { 1 } { x } , g ( x ) = x ^ { 2 } - 6$
D) $f ( x ) = \frac { 1 } { 6 } , g ( x ) = x ^ { 2 } - 6$

Consider the Function H as Defined (f∘g)(x)=h(x)( f \circ g ) ( x ) = h ( x )(f∘g)(x)=h(x)

Consider the Function H as Defined $( f \circ g ) ( x ) = h ( x )$