Find the center-radius form of the equation of the circle.
-center $( - \sqrt { 2 } , - 2 )$, radius $\sqrt { 2 }$
A) $( x + \sqrt { 2 } ) ^ { 2 } + ( y + 2 ) ^ { 2 } = \sqrt { 2 }$
B) $( x - \sqrt { 2 } ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 2$
C) $( x - \sqrt { 2 } ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 4$
D) $( x + \sqrt { 2 } ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 2$

Question

Quizplus · Accepted Answer

The center-radius form of a circle is $(x - h)^2 + (y - k)^2 = r^2$. Here, the center is $(- \sqrt{2}, -2)$ and the radius is $\sqrt{2}$, so the equation is $(x + \sqrt{2})^2 + (y + 2)^2 = (\sqrt{2})^2 = 2$.

Find the Center-Radius Form of the Equation of the Circle (−2,−2)( - \sqrt { 2 } , - 2 )(−2​,−2)

Find the Center-Radius Form of the Equation of the Circle $( - \sqrt { 2 } , - 2 )$