Find the center-radius form of the equation of the circle.
-center $( 0 , - 2 )$, radius $\sqrt { 7 }$
A) $( x - 2 ) ^ { 2 } + y ^ { 2 } = 49$
B) $x ^ { 2 } + ( y + 2 ) ^ { 2 } = 7$
C) $x ^ { 2 } + ( y - 2 ) ^ { 2 } = 7$
D) $( x + 2 ) ^ { 2 } + y ^ { 2 } = 49$

Question

Quizplus · Accepted Answer

The center-radius form of a circle's equation is $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center and $r$ is the radius. Given the center $(0, -2)$ and radius $\sqrt{7}$, the equation becomes $x^2 + (y + 2)^2 = 7$.

Find the Center-Radius Form of the Equation of the Circle (0,−2)( 0 , - 2 )(0,−2)

Find the Center-Radius Form of the Equation of the Circle $( 0 , - 2 )$