The pitch P of a musical tone varies inversely as its wavelength W. One tone has a pitch of 254 vibrations per second and a wavelength of 19.2 ft. Find the wavelength of another tone that has a pitch of 358 vibrations per
Second. Round to the nearest tenth.
A) 0 ft
B) 0.1 ft
C) 13.6 ft
D) 4736 ft

Question

Quizplus · Accepted Answer

The relationship between pitch (P) and wavelength (W) is inversely proportional, meaning $P = k/W$, where $k$ is a constant. For the first tone, $254 = k/19.2$, so $k = 254 \times 19.2$. For the second tone with a pitch of 358 vibrations per second, $358 = k/W$. Substituting the value of $k$ from the first equation, we find the wavelength $W$ for the second tone. Solving for $W$ gives $W \approx 13.6$ ft.

The Pitch P of a Musical Tone Varies Inversely as Its