Give the equations of any horizontal asymptotes.
-$$g ( x ) = \frac { x ^ { 2 } + 8 x - 1 } { x - 1 }$$
A) $y = 0$
B) none
C) $y = - 1$
D) $y = 8$

Question

Quizplus · Accepted Answer

Horizontal asymptotes are found by looking at the behavior of a function as $x$ approaches infinity. For the given function $g(x) = \frac{x^2 + 8x - 1}{x - 1}$, the degree of the numerator is higher than the degree of the denominator, which means the function does not have a horizontal asymptote. Instead, its end behavior is dominated by the highest degree terms, leading to an oblique or slant asymptote, not a horizontal one.

Give the Equations of Any Horizontal Asymptotes g(x)=x2+8x−1x−1g ( x ) = \frac { x ^ { 2 } + 8 x - 1 } { x - 1 }g(x)=x−1x2+8x−1​

Give the Equations of Any Horizontal Asymptotes $g ( x ) = \frac { x ^ { 2 } + 8 x - 1 } { x - 1 }$