Find all rational zeros and factor f(x).
-$$f ( x ) = x ^ { 3 } - 6 x ^ { 2 } + 5 x + 12$$
A) $5,4 , - 1 ; f ( x ) = ( x - 5 ) ( x - 4 ) ( x + 1 )$
B) $4,3 , - 1 ; f ( x ) = ( x - 4 ) ( x - 3 ) ( x + 1 )$
C) $- 5 , - 4,1 ; f ( x ) = ( x + 5 ) ( x + 4 ) ( x - 1 )$
D) $- 4 , - 3,1 ; f ( x ) = ( x + 4 ) ( x + 3 ) ( x - 1 )$

Question

Quizplus · Accepted Answer

The rational zeros of the polynomial $f(x) = x^3 - 6x^2 + 5x + 12$ are 4, 3, and -1. The polynomial can be factored as $f(x) = (x - 4)(x - 3)(x + 1)$.

Find All Rational Zeros and Factor F(x) f(x)=x3−6x2+5x+12f ( x ) = x ^ { 3 } - 6 x ^ { 2 } + 5 x + 12f(x)=x3−6x2+5x+12

Find All Rational Zeros and Factor F(x) $f ( x ) = x ^ { 3 } - 6 x ^ { 2 } + 5 x + 12$