Solve the inequality. Write the solution set in interval notation.
-$$x ^ { 2 } + 4 x - 12

Question

Solve the inequality. Write the solution set in interval notation.
-$$x ^ { 2 } + 4 x - 12 < 0$$
A) $( -\infty , - 6 ) \cup ( 2 , \infty )$
B) $( -\infty , - 2 ) \cup ( 6 , \infty )$
C) $( - 2,6 )$
D) $( - 6,2 )$

Quizplus · Accepted Answer

First, factor the quadratic inequality: $x^2 + 4x - 12 < 0$ can be factored into $(x + 6)(x - 2) < 0$. The roots are $x = -6$ and $x = 2$. The inequality is satisfied for values between the roots, so the solution set is $(-6, 2)$.

Solve the Inequality x2+4x−12<0x ^ { 2 } + 4 x - 12 < 0x2+4x−12<0

Solve the Inequality $x ^ { 2 } + 4 x - 12 < 0$