Find the equation of the axis of symmetry of the parabola.
$y = x ^ { 2 } - 10 x + 26$
A) x=5
B) x=-5
C) x=0
D) x=1

Name: Find the equation of the axis of symmetry of the parabola. $y = x ^ { 2 } - 10 x + 26$ A) x=5 B) x=-5 C) x=0 D) x=1
Brand: Quizplus
Rating: 4.8 (32 reviews)

Question

Find the equation of the axis of symmetry of the parabola.
$y = x ^ { 2 } - 10 x + 26$
A)  x=5 
B)  x=-5 
C)  x=0 
D)  x=1

Quizplus · Accepted Answer

The axis of symmetry for a parabola in the form $y = ax^2 + bx + c$ is given by the formula $x = -\frac{b}{2a}$. For the given equation $y = x^2 - 10x + 26$, $a = 1$ and $b = -10$, so the axis of symmetry is $x = -\frac{-10}{2*1} = 5$.

Find the Equation of the Axis of Symmetry of the Parabola