Round your answer to the nearest tenth, when appropriate. Use the formula $\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$ , as
needed.
-Find the $\left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$if the $\mathrm { pH } = 2.3$.
A) $5.0 \times 10 ^ { - 3 }$
B) $3.6 \times 10 ^ { - 1 }$
C) $2.7 \times 10 ^ { 1 }$
D) $2.0 \times 10 ^ { 2 }$

Question

Quizplus · Accepted Answer

To find $\left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$ given $\mathrm { pH } = 2.3$, use the formula $\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$. Rearranging gives $\left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] = 10^{-\mathrm { pH }} = 10^{-2.3} \approx 5.0 \times 10 ^ { - 3 }$.

Round Your Answer to the Nearest Tenth, When Appropriate pH=−log⁡[H3O+]\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]pH=−log[H3​O+]

Round Your Answer to the Nearest Tenth, When Appropriate $\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$