If the function is one-to-one, find its inverse. If not, write "not one-to-one."
-$$f ( x ) = - \sqrt { x ^ { 2 } - 25 } , x \geq 5$$
A) $f ^ { - 1 } ( x ) = - \sqrt { 25 - x ^ { 2 } } , x \leq 0$
B) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \sqrt { 25 - \mathrm { x } ^ { 2 } } , \mathrm { x } \leq 5$
C) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \sqrt { \mathrm { x } ^ { 2 } + 25 } , \mathrm { x } \geq 0$
D) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \sqrt { \mathrm { x } ^ { 2 } + 25 } , \mathrm { x } \leq 0$

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The Answer of If the function is one-to-one, find its inverse. If not, write "not one-to-one."
-$$f ( x ) = - \sqrt { x ^ { 2 } - 25 } , x \geq 5$$
A) $f ^ { - 1 } ( x ) = - \sqrt { 25 - x ^ { 2 } } , x \leq 0$
B) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \sqrt { 25 - \mathrm { x } ^ { 2 } } , \mathrm { x } \leq 5$
C) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \sqrt { \mathrm { x } ^ { 2 } + 25 } , \mathrm { x } \geq 0$
D) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \sqrt { \mathrm { x } ^ { 2 } + 25 } , \mathrm { x } \leq 0$

If the Function Is One-To-One, Find Its Inverse f(x)=−x2−25,x≥5f ( x ) = - \sqrt { x ^ { 2 } - 25 } , x \geq 5f(x)=−x2−25​,x≥5

If the Function Is One-To-One, Find Its Inverse $f ( x ) = - \sqrt { x ^ { 2 } - 25 } , x \geq 5$