If the function is one-to-one, find its inverse. If not, write "not one-to-one."
-$f ( x ) = - 8 x + 1$
A) $f ^ { - 1 } ( x ) = - \frac { 1 } { 8 } x - 1$
B) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = - \frac { 1 } { 8 } \mathrm { x } - \frac { 1 } { 8 }$
C) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = - \frac { 1 } { 8 } \mathrm { x } + \frac { 1 } { 8 }$
D) $f ^ { - 1 } ( x ) = - \frac { 1 } { 8 } x + 1$

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The Answer of If the function is one-to-one, find its inverse. If not, write "not one-to-one."
-$f ( x ) = - 8 x + 1$
A) $f ^ { - 1 } ( x ) = - \frac { 1 } { 8 } x - 1$
B) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = - \frac { 1 } { 8 } \mathrm { x } - \frac { 1 } { 8 }$
C) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = - \frac { 1 } { 8 } \mathrm { x } + \frac { 1 } { 8 }$
D) $f ^ { - 1 } ( x ) = - \frac { 1 } { 8 } x + 1$

If the Function Is One-To-One, Find Its Inverse f(x)=−8x+1f ( x ) = - 8 x + 1f(x)=−8x+1

If the Function Is One-To-One, Find Its Inverse $f ( x ) = - 8 x + 1$