Match the equation of a hyperbola with its description.
-$$\frac { ( x + 2 ) ^ { 2 } } { 64 } - \frac { ( y + 3 ) ^ { 2 } } { 25 } = 1$$
A) center $( 2,3 )$; horizontal transverse axis
B) center $( 3,2 )$; vertical transverse axis
C) center $( - 3 , - 2 )$; vertical transverse axis
D) center $( - 2 , - 3 )$; horizontal transverse axis

Question

Quizplus · Accepted Answer

The equation of a hyperbola in the form $\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1$ has its center at $(h, k)$ and a horizontal transverse axis if $a^2$ is under the $x$ term. For the given equation, the center is $(-2, -3)$ and the transverse axis is horizontal because the $x$-term is positive and comes first.

Match the Equation of a Hyperbola with Its Description (x+2)264−(y+3)225=1\frac { ( x + 2 ) ^ { 2 } } { 64 } - \frac { ( y + 3 ) ^ { 2 } } { 25 } = 164(x+2)2​−25(y+3)2​=1

Match the Equation of a Hyperbola with Its Description $\frac { ( x + 2 ) ^ { 2 } } { 64 } - \frac { ( y + 3 ) ^ { 2 } } { 25 } = 1$