A satellite is to be put into an elliptical orbit around a moon. The moon is a sphere with radius of 578 km. Determine an equation for the ellipse if the distance of the satellite from the surface of the moon varies from 490
Km to 261 km.
A) $\frac { x ^ { 2 } } { 839 ^ { 2 } } + \frac { y ^ { 2 } } { 1068 ^ { 2 } } = 1$
B) $\frac { x ^ { 2 } } { 261 } + \frac { y ^ { 2 } } { 490 } = 1$
C) $\frac { x ^ { 2 } } { 1068 ^ { 2 } } + \frac { y ^ { 2 } } { 839 ^ { 2 } } = 1$
D) $\frac { x ^ { 2 } } { 490 } + \frac { y ^ { 2 } } { 261 } = 1$

Question

A satellite is to be put into an elliptical orbit around a moon. The moon is a sphere with radius of 578 km. Determine an equation for the ellipse if the distance of the satellite from the surface of the moon varies from 490
Km to 261 km. 
A) $\frac { x ^ { 2 } } { 839 ^ { 2 } } + \frac { y ^ { 2 } } { 1068 ^ { 2 } } = 1$ 
B) $\frac { x ^ { 2 } } { 261 } + \frac { y ^ { 2 } } { 490 } = 1$ 
C) $\frac { x ^ { 2 } } { 1068 ^ { 2 } } + \frac { y ^ { 2 } } { 839 ^ { 2 } } = 1$ 
D) $\frac { x ^ { 2 } } { 490 } + \frac { y ^ { 2 } } { 261 } = 1$

Quizplus · Accepted Answer

The Answer of A satellite is to be put into an elliptical orbit around a moon. The moon is a sphere with radius of 578 km. Determine an equation for the ellipse if the distance of the satellite from the surface of the moon varies from 490
Km to 261 km. 
A) $\frac { x ^ { 2 } } { 839 ^ { 2 } } + \frac { y ^ { 2 } } { 1068 ^ { 2 } } = 1$ 
B) $\frac { x ^ { 2 } } { 261 } + \frac { y ^ { 2 } } { 490 } = 1$ 
C) $\frac { x ^ { 2 } } { 1068 ^ { 2 } } + \frac { y ^ { 2 } } { 839 ^ { 2 } } = 1$ 
D) $\frac { x ^ { 2 } } { 490 } + \frac { y ^ { 2 } } { 261 } = 1$

A Satellite Is to Be Put into an Elliptical Orbit x28392+y210682=1\frac { x ^ { 2 } } { 839 ^ { 2 } } + \frac { y ^ { 2 } } { 1068 ^ { 2 } } = 18392x2​+10682y2​=1

A Satellite Is to Be Put into an Elliptical Orbit $\frac { x ^ { 2 } } { 839 ^ { 2 } } + \frac { y ^ { 2 } } { 1068 ^ { 2 } } = 1$