If an object is thrown upward with an initial velocity of 10 ft per second, then its height is given by h = -10t2 + 80t. What is its maximum height?
A) 120 ft
B) 80 ft
C) 240 ft
D) 160 ft

Question

Quizplus · Accepted Answer

The maximum height is found at the vertex of the parabola represented by the equation h = -10t^2 + 80t. The vertex occurs at t = -b/(2a) = -80/(2*(-10)) = 4 seconds. Plugging t = 4 into the equation gives h = -10(4)^2 + 80(4) = 160 ft.

If an Object Is Thrown Upward with an Initial Velocity