Find a general term a n for the geometric sequence.
-$$a _ { 1 } = \frac { 1 } { 4 } , r = 8$$
A) $a _ { n } = \frac { 1 } { 4 } \cdot 8 ^ { n - 1 }$
B) $a _ { n } = \frac { 1 } { 4 } + \frac { 7 } { 4 } ( n - 1 )$
C) $a _ { n } = \left( \frac { 1 } { 4 } \right) n - 1 + \frac { 7 } { 4 }$
D) $a _ { n } = \frac { 1 } { 4 } + 8 ( n - 1 )$

Question

Quizplus · Accepted Answer

The general term for a geometric sequence is given by $a_n = a_1 \cdot r^{n-1}$, where $a_1$ is the first term and $r$ is the common ratio. Given $a_1 = \frac{1}{4}$ and $r = 8$, the formula becomes $a_n = \frac{1}{4} \cdot 8^{n-1}$.

Find a General Term An for the Geometric Sequence a1=14,r=8a _ { 1 } = \frac { 1 } { 4 } , r = 8a1​=41​,r=8

Find a General Term A_n for the Geometric Sequence $a _ { 1 } = \frac { 1 } { 4 } , r = 8$