Use the summation properties to evaluate the series. The following rules may be needed: $$\sum _ { i = 1 } ^ { n } i = \frac { n ( n + 1 ) } { 2 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 2 } = \frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 3 } = \frac { n ^ { 2 } ( n + 1 ) ^ { 2 } } { 4 }$$
-$$\sum _ { i = 1 } ^ { 5 } ( - 3 i - 4 )$$
A) $- 33$
B) $- 85$
C) $- 45$
D) $- 65$

Question

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The Answer of Use the summation properties to evaluate the series. The following rules may be needed: $$\sum _ { i = 1 } ^ { n } i = \frac { n ( n + 1 ) } { 2 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 2 } = \frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 3 } = \frac { n ^ { 2 } ( n + 1 ) ^ { 2 } } { 4 }$$
-$$\sum _ { i = 1 } ^ { 5 } ( - 3 i - 4 )$$
A) $- 33$
B) $- 85$
C) $- 45$
D) $- 65$

Use the Summation Properties to Evaluate the Series - ∑i=15(−3i−4)\sum _ { i = 1 } ^ { 5 } ( - 3 i - 4 )i=1∑5​(−3i−4)

Use the Summation Properties to Evaluate the Series - $\sum _ { i = 1 } ^ { 5 } ( - 3 i - 4 )$