First, write the value(s) that make the denominator(s) zero. Then solve the equation.
-$$\frac { 2 } { y + 5 } - \frac { 6 } { y - 5 } = \frac { 4 } { y ^ { 2 } - 25 }$$
A) $\{ - 11 \}$
B) $\{ 11 \}$
C) $\{ \sqrt { 33 } \}$
D) $\{ 44 \}$

Question

Quizplus · Accepted Answer

CThe values that make the denominators zero are $y = -5$ and $y = 5$, since $y^2 - 25 = (y + 5)(y - 5)$. Solving the equation, we get $y = -11$ and $y = \sqrt{33}$.

First, Write the Value(s) That Make the Denominator(s) Zero 2y+5−6y−5=4y2−25\frac { 2 } { y + 5 } - \frac { 6 } { y - 5 } = \frac { 4 } { y ^ { 2 } - 25 }y+52​−y−56​=y2−254​

First, Write the Value(s) That Make the Denominator(s) Zero $\frac { 2 } { y + 5 } - \frac { 6 } { y - 5 } = \frac { 4 } { y ^ { 2 } - 25 }$