Solve.
-The value of a particular investment follows a pattern of exponential growth. In the year 2000, you invested money in a money market account. The value of your investment t years after 2000 is given by the exponential growth model $\mathrm { A } = 2600 \mathrm { e } ^ { 0.052 \mathrm { t } }$. How much did you initially invest in the account?
A) $\$ 2600.00$
B) $\$ 2738.78$
C) $\$ 135.20$
D) $\$ 1300.00$

Question

Quizplus · Accepted Answer

The initial investment is found by evaluating the exponential growth model at $t = 0$, which gives $A = 2600e^{0.052(0)} = 2600e^0 = 2600$.

Solve -The Value of a Particular Investment Follows a Pattern A=2600e0.052t\mathrm { A } = 2600 \mathrm { e } ^ { 0.052 \mathrm { t } }A=2600e0.052t

Solve
-The Value of a Particular Investment Follows a Pattern $\mathrm { A } = 2600 \mathrm { e } ^ { 0.052 \mathrm { t } }$