Solve the problem.
-The current I, in amperes, flowing through a particular ac (alternating current) circuit at time $t$ seconds is
$$I = 110 \sin \left( 35 \pi t - \frac { \pi } { 8 } \right)$$
What is the period of the current?
A) $\frac { 2 } { 35 }$ second
B) $35 \pi$ seconds
C) $\frac { 1 } { 280 }$ second
D) $\frac { \pi } { 110 }$ second

Question

Quizplus · Accepted Answer

The period of a sine function $ \sin(bt) $ is given by $ \frac{2\pi}{b} $. In the given function, $ b = 35\pi $, so the period is $ \frac{2\pi}{35\pi} = \frac{2}{35} $ seconds.

Solve the Problem ttt Seconds Is I=110sin⁡(35πt−π8)I = 110 \sin \left( 35 \pi t - \frac { \pi } { 8 } \right)I=110sin(35πt−8π​)

Solve the Problem $t$ Seconds Is $I = 110 \sin \left( 35 \pi t - \frac { \pi } { 8 } \right)$