Determine the phase shift of the function.
-$$y = \frac { 1 } { 2 } \sin ( 3 x + \pi )$$
A) $\frac { \pi } { 3 }$ units to the left
B) $\frac { \pi } { 2 }$ units to the right
C) $- \frac { \pi } { 3 }$ units to the left
D) $\pi$ units to the left

Question

Quizplus · Accepted Answer

The phase shift of a trigonometric function in the form $y = a \sin(bx + c)$ or $y = a \cos(bx + c)$ is calculated as $-\frac{c}{b}$. For the given function $y = \frac{1}{2} \sin(3x + \pi)$, the phase shift is $-\frac{\pi}{3}$ units, which means the graph is shifted $\frac{\pi}{3}$ units to the left.

Determine the Phase Shift of the Function y=12sin⁡(3x+π)y = \frac { 1 } { 2 } \sin ( 3 x + \pi )y=21​sin(3x+π)

Determine the Phase Shift of the Function $y = \frac { 1 } { 2 } \sin ( 3 x + \pi )$