Solve Problems Using Systems of Nonlinear Equations
-In a 1-Mile $16.03 \mathrm { ft }$

Solve Problems Using Systems of Nonlinear Equations
-In a 1-mile race, the winner crosses the finish line 11 feet ahead of the second-place runner and 27 feet ahead of the third-place runner. Assuming that each runner maintains a constant speed throughout the race, by how many feet does the second-place runner beat the third-place runner? ( 5280 feet in 1 mile.)

A) $16.03 \mathrm { ft }$
B) $- 11.06 \mathrm { ft }$
C) $- 16.08 \mathrm { ft }$
D) $5.01 \mathrm { ft }$