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Solve Applied Problems Involving Parabolas
-A Satellite Dish Is in the Shape

Question 103

Multiple Choice

Solve Applied Problems Involving Parabolas
-A satellite dish is in the shape of a parabolic surface. Signals coming from a satellite strike the surface of the dish and are reflected to the focus, where the receiver is located. The satellite dish shown has a diameter of 6 feet and a depth of 6 feet. The parabola is positioned in a rectangular coordinate system with its vertex at the origin. The receiver should be placed at the focus (0,p) ( 0 , \mathrm { p } ) . The value of p\mathrm { p } is given by the equation a=14p\mathrm { a } = \frac { 1 } { 4 \mathrm { p } } . How far from the base of the dish should the receiver be placed?.
 Solve Applied Problems Involving Parabolas -A satellite dish is in the shape of a parabolic surface. Signals coming from a satellite strike the surface of the dish and are reflected to the focus, where the receiver is located. The satellite dish shown has a diameter of 6 feet and a depth of 6 feet. The parabola is positioned in a rectangular coordinate system with its vertex at the origin. The receiver should be placed at the focus  ( 0 , \mathrm { p } )  . The value of  \mathrm { p }  is given by the equation  \mathrm { a } = \frac { 1 } { 4 \mathrm { p } } . How far from the base of the dish should the receiver be placed?.    A)   \frac { 3 } { 8 }  feet from the base B)   1 \frac { 1 } { 2 }  feet from the base C)   \frac { 2 } { 3 }  feet from the base D)   2 \frac { 2 } { 3 }  feet from the base


A) 38\frac { 3 } { 8 } feet from the base
B) 1121 \frac { 1 } { 2 } feet from the base
C) 23\frac { 2 } { 3 } feet from the base
D) 2232 \frac { 2 } { 3 } feet from the base

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