Solve the problem.
-A wire of length $3 x$ is bent into the shape of a square. Express the area A of the square as a function of x.
A) $A ( x ) = \frac { 3 } { 4 } x ^ { 2 }$
B) $A ( x ) = \frac { 9 } { 16 } x ^ { 2 }$
C) $\mathrm { A } ( \mathrm { x } ) = \frac { 9 } { 8 } \mathrm { x } ^ { 2 }$
D) $A ( x ) = \frac { 1 } { 16 } x ^ { 2 }$

Question

Quizplus · Accepted Answer

The perimeter of the square is equal to the length of the wire, which is $3x$. Since a square has four equal sides, each side is $\frac{3x}{4}$ long. The area of a square is given by the square of the side length, so $A(x) = \left(\frac{3x}{4}\right)^2 = \frac{9}{16}x^2$.

Solve the Problem 3x3 x3x Is Bent into the Shape of a Square

Solve the Problem $3 x$ Is Bent into the Shape of a Square