Find an equation of the secant line containing (1, f(1)) and (2, f(2)).
-$$f ( x ) = \frac { 4 } { x + 3 }$$
A) $y = \frac { 1 } { 5 } x + \frac { 4 } { 5 }$
B) $y = \frac { 4 } { 5 } x + \frac { 1 } { 5 }$
C) $y = - \frac { 1 } { 5 } x + \frac { 6 } { 5 }$
D) $y = \frac { 1 } { 5 } x + \frac { 3 } { 2 }$

Question

Quizplus · Accepted Answer

To find the equation of the secant line, calculate the slope using the points (1, f(1)) and (2, f(2)). f(1) = 1 and f(2) = 2/5. The slope is (2/5 - 1)/(2 - 1) = -3/5. Using point-slope form with point (1, 1), the equation is y - 1 = -3/5(x - 1), simplifying to y = -1/5x + 6/5.

Find an Equation of the Secant Line Containing (1, F(1)) f(x)=4x+3f ( x ) = \frac { 4 } { x + 3 }f(x)=x+34​

Find an Equation of the Secant Line Containing (1, F(1)) $f ( x ) = \frac { 4 } { x + 3 }$