Find the value for the function.
-Find $f ( 2 x )$ when $f ( x ) = - 2 x ^ { 2 } - 3 x + 1$
A) $- 8 x ^ { 2 } - 6 x + 1$
B) $- 8 x ^ { 2 } - 6 x + 2$
C) $- 4 x ^ { 2 } - 6 x + 2$
D) $- 4 x ^ { 2 } - 6 x + 1$

Question

Quizplus · Accepted Answer

To find $f(2x)$, substitute $2x$ for every $x$ in the original function $f(x) = -2x^2 - 3x + 1$. This gives $f(2x) = -2(2x)^2 - 3(2x) + 1 = -8x^2 - 6x + 1$.

Find the Value for the Function f(2x)f ( 2 x )f(2x)

Find the Value for the Function $f ( 2 x )$