Solve the system of equations.
-$$\left\{ \begin{array} { l }
x - y + z = 8 \
x + y + z = 6 \
x + y - z = - 12
\end{array} \right.$$
A) $x = 2 , y = - 1 , z = - 9$
B) $x = - 2 , y = - 1 , z = - 9$
C) $x = - 2 , y = - 1 , z = 9$
D) $x = 2 , y = - 1 , z = 9$

Question

Solve the system of equations.
-$$\left\{ \begin{array} { l } 
x - y + z = 8 \
x + y + z = 6 \
x + y - z = - 12
\end{array} \right.$$
A) $x = 2 , y = - 1 , z = - 9$
B) $x = - 2 , y = - 1 , z = - 9$
C) $x = - 2 , y = - 1 , z = 9$
D) $x = 2 , y = - 1 , z = 9$

Quizplus · Accepted Answer

The Answer of Solve the system of equations.
-$$\left\{ \begin{array} { l } 
x - y + z = 8 \
x + y + z = 6 \
x + y - z = - 12
\end{array} \right.$$
A) $x = 2 , y = - 1 , z = - 9$
B) $x = - 2 , y = - 1 , z = - 9$
C) $x = - 2 , y = - 1 , z = 9$
D) $x = 2 , y = - 1 , z = 9$

Solve the System of Equations {x−y+z=8x+y+z=6x+y−z=−12\left\{ \begin{array} { l } x - y + z = 8 \\x + y + z = 6 \\x + y - z = - 12\end{array} \right.⎩⎨⎧​x−y+z=8x+y+z=6x+y−z=−12​

Solve the System of Equations $\left\{ \begin{array} { l } x - y + z = 8 \\x + y + z = 6 \\x + y - z = - 12\end{array} \right.$