Determine whether f is continuous at c.
-$$f ( x ) = \frac { x ^ { 2 } - 25 } { x - 5 } ; \quad c = 0$$
A) not continuous
B) continuous

Question

Quizplus · Accepted Answer

The function $f(x) = \frac{x^2 - 25}{x - 5}$ simplifies to $f(x) = x + 5$ when $x \neq 5$, since $x^2 - 25 = (x + 5)(x - 5)$. At $c = 0$, the function is defined and equals $0 + 5 = 5$, and the limit as $x$ approaches 0 is also 5. Therefore, $f$ is continuous at $c = 0$.

Determine Whether F Is Continuous at C f(x)=x2−25x−5;c=0f ( x ) = \frac { x ^ { 2 } - 25 } { x - 5 } ; \quad c = 0f(x)=x−5x2−25​;c=0

Determine Whether F Is Continuous at C $f ( x ) = \frac { x ^ { 2 } - 25 } { x - 5 } ; \quad c = 0$