Determine I) the Domain of the Function, Ii) the Range $f ( x ) = \sqrt { 5 x + 4 }$

Determine i) the domain of the function, ii) the range of the function, iii) the domain of the inverse, and iv) the range of
the inverse.
- $f ( x ) = \sqrt { 5 x + 4 }$

A) $$f(x) : D=\left\{x \mid x \geq-\frac{4}{5}\right\}, R=\{y \mid y \geq 0\}$$
$f^{-1}(x) : D$ is all real numbers, $R=\left\{y \mid y \geq-\frac{4}{5}\right\}$

B) $f ( x ) : D = \left\{ x \mid x \geq - \frac { 4 } { 5 } \right\} , R = \{ y \mid y \geq 0 \}$ ; $\mathrm { f } ^ { - 1 } ( \mathrm { x } )$ : $\mathrm { D }$ is all real numbers, $\mathrm { R } = \left\{ \mathrm { y } \mid \mathrm { y } \geq - \frac { 4 } { 5 } \right\}$ $\mathrm { f } - 1 ( \mathrm { x } ) : \mathrm { D } = \left\{ \mathrm { x } | \mathrm { x } \geq 0 \rangle , \mathrm { R } = \left\{ \mathrm { y } \mid \mathrm { y } \geq - \frac { 4 } { 5 } \right\} \right.$

C) $f ( x ) : D = \left\{ x \mid x \geq - \frac { 4 } { 5 } \right\} , R$ is all real numbers;
$f^{-1}(x) : D \text { is all real numbers, } R=\left\{y \mid y \geq-\frac{4}{5}\right\}$

D)
$\begin{array}{l}f(x) : D=\{x \mid x \geq 0\}, R=\{y \mid y \geq 0\} \\f^{-1}(x) : D=\{x \mid x \geq 0\}, R=\left\{y \mid y \geq-\frac{4}{5}\right\}\end{array}$