Solve the problem using Snell's Law: $$\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { v _ { 1 } } { v _ { 2 } }$$
-A ray of light near the horizon with an angle of incidence of $77 ^ { \circ }$ enters a pool of water and strikes a fish's eye. If the index of refraction is $1.33$, what is the angle of refraction (to two decimal places)?
A) $42.89 ^ { \circ }$
B) $46.20 ^ { \circ }$
C) $47.11 ^ { \circ }$
D) $43.80 ^ { \circ }$

Question

Quizplus · Accepted Answer

Using Snell's Law, $ n_1 \sin \theta_1 = n_2 \sin \theta_2 $. Here, $ n_1 = 1 $ (air), $ n_2 = 1.33 $ (water), and $ \theta_1 = 77^\circ $. Solving for $ \theta_2 $, we get $ \sin \theta_2 = \frac{\sin 77^\circ}{1.33} $. Calculating gives $ \theta_2 \approx 47.11^\circ $.

Solve the Problem Using Snell's Law sin⁡θ1sin⁡θ2=v1v2\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { v _ { 1 } } { v _ { 2 } }sinθ2​sinθ1​​=v2​v1​​

Solve the Problem Using Snell's Law $\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { v _ { 1 } } { v _ { 2 } }$