Consider the given discrete probability distribution. Find the probability that x equals 4. $$\begin{array} { l | c c c c }
x & 2 & 4 & 7 & 8 \
\hline P ( x ) & 0.24 & ? & 0.28 & 0.01
\end{array}$$
A) 0.53
B) 1.88
C) 2.12
D) 0.47

Question

Consider the given discrete probability distribution. Find the probability that x equals 4. $$\begin{array} { l | c c c c } 
x & 2 & 4 & 7 & 8 \
\hline P ( x ) & 0.24 & ? & 0.28 & 0.01
\end{array}$$
A) 0.53
B) 1.88
C) 2.12
D) 0.47

Quizplus · Accepted Answer

The sum of all probabilities in a discrete probability distribution must equal 1. Therefore, the missing probability for x = 4 is 1 - (0.24 + 0.28 + 0.01) = 0.47.

Consider the Given Discrete Probability Distribution x2478P(x)0.24?0.280.01\begin{array} { l | c c c c } x & 2 & 4 & 7 & 8 \\\hline P ( x ) & 0.24 & ? & 0.28 & 0.01\end{array}xP(x)​20.24​4?​70.28​80.01​​

Consider the Given Discrete Probability Distribution $\begin{array} { l | c c c c } x & 2 & 4 & 7 & 8 \\\hline P ( x ) & 0.24 & ? & 0.28 & 0.01\end{array}$