Solve the problem.
-The length of the diagonal of a box is given by $D = \sqrt { L ^ { 2 } + W ^ { 2 } + H ^ { 2 } }$ where $L , W$, and $H$ are the length, width, and height of the box. Find the length of the diagonal, D, of a box that is $4 \mathrm { ft }$ long, $2 \mathrm { ft }$ high, and $4 \mathrm { ft }$ wide. Give the exact value.
A) $6 \mathrm { ft }$
B) $4 \sqrt { 2 } \mathrm { ft }$
C) $10 \mathrm { ft }$
D) $32 \mathrm { ft }$

Question

Quizplus · Accepted Answer

The length of the diagonal $D$ can be found by substituting $L = 4$, $W = 4$, and $H = 2$ into the formula $D = \sqrt { L ^ { 2 } + W ^ { 2 } + H ^ { 2 } }$, resulting in $D = \sqrt { 4^2 + 4^2 + 2^2 } = \sqrt { 16 + 16 + 4 } = \sqrt { 36 } = 6 \mathrm { ft }$.

Solve the Problem D=L2+W2+H2D = \sqrt { L ^ { 2 } + W ^ { 2 } + H ^ { 2 } }D=L2+W2+H2​

Solve the Problem $D = \sqrt { L ^ { 2 } + W ^ { 2 } + H ^ { 2 } }$