Factor by any method.
-$$8 s ^ { 3 } + 1$$
A) $( 2 s - 1 ) \left( 4 s ^ { 2 } + 2 s + 1 \right)$
B) $( 2 s + 1 ) \left( 4 s ^ { 2 } - 2 s + 1 \right)$
C) $( 2 \mathrm {~s} + 1 ) \left( 4 \mathrm {~s} ^ { 2 } + 1 \right)$
D) $( 8 s + 1 ) \left( s ^ { 2 } - 2 s + 1 \right)$

Question

Quizplus · Accepted Answer

The expression $8s^3 + 1$ is a sum of cubes, which can be factored as $(a^3 + b^3) = (a + b)(a^2 - ab + b^2)$. Here, $a = 2s$ and $b = 1$, so the factored form is $(2s + 1)(4s^2 - 2s + 1)$.

Factor by Any Method 8s3+18 s ^ { 3 } + 18s3+1

Factor by Any Method $8 s ^ { 3 } + 1$